更新時間:2022-04-15 09:42:13 來源:動力節點 瀏覽1315次
一個基本的計算器能夠加、減、乘或除兩個數字。這是使用開關盒完成的。演示這一點的程序如下
例子
import java.util.Scanner;
public class Calculator {
public static void main(String[] args) {
double num1;
double num2;
double ans;
char op;
Scanner reader = new Scanner(System.in);
System.out.print("Enter two numbers: ");
num1 = reader.nextDouble();
num2 = reader.nextDouble();
System.out.print("\nEnter an operator (+, -, *, /): ");
op = reader.next().charAt(0);
switch(op) {
case '+': ans = num1 + num2;
break;
case '-': ans = num1 - num2;
break;
case '*': ans = num1 * num2;
break;
case '/': ans = num1 / num2;
break;
default: System.out.printf("Error! Enter correct operator");
return;
}
System.out.print("\nThe result is given as follows:\n");
System.out.printf(num1 + " " + op + " " + num2 + " = " + ans);
}
}
輸出
Enter two numbers: 10.0 7.0
Enter an operator (+, -, *, /): -
The result is given as follows:
10.0 - 7.0 = 3.0
現在讓我們了解一下上面的程序。
這兩個號碼以及運營商都是從用戶那里獲取的。演示這一點的代碼片段如下
double num1;
double num2;
double ans;
char op;
Scanner reader = new Scanner(System.in);
System.out.print("Enter two numbers: ");
num1 = reader.nextDouble();
num2 = reader.nextDouble();
System.out.print("\nEnter an operator (+, -, *, /): ");
op = reader.next().charAt(0);
switch case 用于對兩個數字執行指定的操作。如果輸入的操作員不正確,則會顯示錯誤消息。演示這一點的代碼片段如下
switch(op) {
case '+': ans = num1 + num2;
break;
case '-': ans = num1 - num2;
break;
case '*': ans = num1 * num2;
break;
case '/': ans = num1 / num2;
break;
default: System.out.printf("Error! Enter correct operator");
return;
}
最后,打印結果。演示這一點的代碼片段如下
System.out.print("\nThe result is given as follows:\n");
System.out.printf(num1 + " " + op + " " + num2 + " = " + ans);
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